2 3 H 6 5h
What is 2 3 H 6 5h?
2 3 H 6 5h is a mathematical expression that is used to identify a pattern in a series of numbers. It is a sequence of numbers where each number is the sum of the two previous numbers. The sequence starts with 2, 3 and then continues in the following order: 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, and so on.How is 2 3 H 6 5h Used?
2 3 H 6 5h is used in a variety of ways, from helping to solve mathematical equations to predicting trends in finance and economics. It is also used in computer programming and is a useful tool for understanding the natural world. In addition, it can be used to create interesting patterns in music, art, and design.What are the Benefits of 2 3 H 6 5h?
Using 2 3 H 6 5h can help you understand patterns and relationships between numbers. It can also help you make faster calculations and solve complex problems. Additionally, it can provide insight into the natural order of the universe, including the behavior of plants, animals, and stars.What are the Limitations of 2 3 H 6 5h?
2 3 H 6 5h is a limited expression and can only be used to identify patterns in certain types of sequences. Furthermore, it is not suitable for solving equations with multiple variables.Conclusion
2 3 H 6 5h is a useful expression that can help you identify patterns in certain types of sequences. It can be applied to a variety of fields, from mathematics to computer programming. However, it is limited in its scope and should not be used to solve equations with multiple variables.Related Video:
Questions and Answers:
1. 6 + 2g -5h -5h+2g +2=
6+2g-5h-5h+2g+2 = 8+4g-10h6 + 2g -5h -5h+2g +2=
6+2+2g+2g-5h-5h=8+4g-10h
2. (6+2z-5h)-(5h-2z-2)..
6+2z-5h -5h + 2z + 2
= -10h + 4z + 8(6+2z-5h)-(5h-2z-2)
= 6+2z-5h - 5h+2z+2
= 6+2+2z+2z-5h-5h
= 8+4z-10h.
3. (6+2g-5h) dari (5h-2g-2)
Mapel : Matematika
Kelas : VII SMP
Bab : Aljabar
Pembahasan :
(5h - 2g - 2) - (6 + 2g - 5h)
= 5h - 2g - 2 - 6 - 2g + 5h
= 10h - 4g - 8Materi: Algebra
(5h - 2g - 2) - (6 + 2g - 5h)
= 5h + 5h - 2g - 2g - 2 - 6
= 10h - 4g - 8
4. h = ( x - 1 )³nilai 5h =.......
Diket:
h = ( x – 1 )³
Ditanya:
Nilai 5h ?...
Jawab:
5h = 5 ( x – 1 )³
5h = 5 ( x – 1 ) ( x – 1 ) ( x – 1 )
5h = 5 ( x³ – 3x² + 3x – 1 )
5h = 5x³ – 15x² + 15x – 5
Kesimpulan:
Nilai 5h = 5x³ – 15x² + 15x – 5 ✅
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# Cmiiw
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➢➢ Penjelasan Dengan Langkah Langkah↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓
Hitung nilai h
[tex]\rm h=(x-1)^{3} [/tex]
[tex]\rm =(x-1)(x-1)(x-1) [/tex]
[tex]\rm =(x^{2}-2x+1)(x-1) [/tex]
[tex]\rm =x^{3}-2x^{2}+x-x^{2}+2x-1 [/tex]
[tex]\rm =x^{3}-3x^{2}+3x-1 [/tex]
Nilai 5h
[tex]\rm = 5(x^{3}-3x^{2}+3x-1) [/tex]
[tex]\rm =5x^{3}-15x^{2}+15x-5 [/tex]
↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑
DETAIL JAWABAN❐ Mapel: Matematika❐ Kode Soal: 2❐ Materi: Aljabar❐ Kata Kunci: -5. tentukan spldv 5h + 2k = -3 dan -5h - 3k = 2 8m - 3n = -12 dan -2m +3n = -6 dengan metode eliminasi
Jawaban:
k=1 h-1 ; m=-3 n=-4
Penjelasan dengan langkah-langkah:
langkah ada di foto
6. 5h + 7k – 3(h + 4k)
Jawaban:
5h + 7k - 3(h + 4k) =
5h + 7k - 3h - 12k =
5h + ( -3h ) + 7k - 12k = 2h - 5k
semoga benar
semoga membantu
7. Tentukan nilai h dari persamaan 3(2h + 5) = 5h + 20
6h + 15 = 5h + 20
h = 5
8. Tentukan nilai h dari 3(2h + 5) = 5h + 20
3(2h + 5) = 5h + 20
6h - 5h = 20 - 15
h = 53(2h + 5) = 5h + 20
<=> 6h + 15 = 5h + 20
<=> 6h - 5h = 20 - 15
<=> h = 5
Jadi nilai h adalah 5
9. Himpunan penyelesaian dari 5h-1 kurang dari sama dengan 4 (3-2h) untuk h € B adalah
5h-1 ≤ 4(3-2h)
5h-1 ≤ 12-8h
13h ≤ 13
h ≤ 1<=>5h-1 kurang dari sama dengan 12-8h
<=>5h+8h kurang dari sama dengan 12+1
<=>13h kurang dari sama dengan 13
<=>h kurang dari sama dengan 1
h : {1,-1,-2,-3,-4,-5,-6......}
10. Diketahui d = 3/4 r. Dan r = 2/5h. Perbandingan d, r, dan h adalah.
[tex]\large{\colorbox{lavender}{\purple{\boxed{\green{\star{\purple{\rm{«Perbandingan» \green{\star}}}}}}}}}[/tex]
Jawaban:3:4:5
Pengerjaan Soal:D=3/4r
D:r=3:4....(1)
==================
r=2/5h
r:h=2:5...X2
r:h=4:5.....(2)
=================
D:r:h
3:4:5
Detail Jawaban:Mapel: Matematika
Kelas:6
Materi:Bab 9.Perbandingan Senilai dan Bertingkat
Kode Soal:2
Kode Kategorisasi:6.2.9
11. Tentukan hasil bagi dari=A. (5H-15):5 B. (H²-H-6) : (H+2)tolong bantu jawab dong kak soalnya nanti malam dikirim
Jawaban:
(H-3)(H+2) (H-3) : (H+2) = (H-3)12. Diketahui d = 3/4 r. Dan r = 2/5h. Perbandingan d, r, dan h adalah
Jawaban:
3 : 4 : 10
Penjelasan:
D : R = 3 : 4
R : H = 2 : 5
yg atas dikalikan 2 yg bawah dikalikan 4
D : R : H = 6 : 8 : 20
= 3 : 4 : 10
Jadi perbandingan D, R,H adalah 3 : 4 : 10
SEMOGA MEMBANTU
13. Sebuah benda jatuh bebas dari ketinggian H, jika pada suatu titik perbandingan energi kinetik dan energi potensialnya adalah 1:4 maka ketinggian saat itu adalah.. A. 1/4H B. 1/5H C. 4/5H D. 3/5H E. 2/5H
• Ep1+Ek1=Ep2+Ek2
• m g h+0=Ep2+3Ep2
• m g h = 4 m g h2
• 1/4h = h2
jadi energi kinetiknya 3x dari energi potensialnya, yaitu waktu tinggi benda 1/4 tinggi awalnya
jawabannya (A)1/4H
14. 2s + 5h = 26½s + ⅔h = 3maka nilai dari s - h = .....
Jawaban:
2(s + 3) + 7(s - 3) = 5(s - 1)2s + 6 + 7s - 21 = 5s - 52s + 7s + 6 - 21 = 5s - 59s - 15 = 5s - 59s - 5s = 15 - 54s = 10s = 10/4s = 5/22s = 2(5/2)2s = 5Moga Membantu Dan Bermanfaat
Maaf Kalo Salah Jawabannya
15. 3(2h+5) = 5h + 20 jumlah h??
maka nilai h = 5
( tolong jadikan yang terbaik)3(2h+5)=5h+20
6h+15=5h+20
6h-5h=20-15
h=5
16. 20h + 5h + - h=.......
Jawaban:
=20h+5h+ -h
=25h-1h
=24h
Penjelasan dengan langkah-langkah:
maaf klo salah
Jawaban:
24h
Penjelasan dengan langkah-langkah:
20h+5h+(-)h
》20h+5h-h
》24h
semogamembantuyaa
17. jika g:h=3:4 maka (6g+h):(4g+5h) adalah
11:16 maaf kalau salah
18. Carilah akar ² persamaan kuadrat berikut ini dengan cara memfaktorkan : h²+5h+3=0
Jawab:
[tex]h^{2}+5h+3=0\\(h+\frac{5}{2}+\frac{1}{2}\sqrt{13})(h+\frac{5}{2}-\frac{1}{2}\sqrt{13})=0\\[/tex]
h = [tex]-\frac{5}{2}-\frac{1}{2}\sqrt{13}[/tex] atau h = [tex]\frac{1}{2}\sqrt{13} - \frac{5}{2}[/tex]
19. Tolong bantu gan/sis beserta caranya juga ya . . . Diketahui f(x) = 5x. Nilai f(2+h) – f(2) = a. h b. 2h c. 5h d. 2 + h e. 10 + 5h
f(2+h)
= 5(2+h)
= 10+5h
f(2)
= 5(2)
= 10
f(2+h) - f(2)
= 10+ 5h -10
= 5hf(x)= 5x
f(2+h)=5(2+h)
= 10 + 5h
f(2) = 5 . 2 = 10
maka, f(2+h) - f(2) = 10 + 5h - 10 = 5h
20. jika g : h = 3:4 maka, (6g + h) : ( 4g + 5h) adalah....
g : h = 3 : 4
(6g + h) : (4g + 5h)
(6.3x + 4x ) : (4.3x + 5.4x)
(18x + 4x ) : (12x + 20x)
22x : 32x
11 : 16
Jadi, (6g+h) : (4g+5h) = 11 : 16
